TV LEGO Masters - Celebrity Holiday Bricktacular LEGO Masters - Celebrity Holiday Bricktacular 7.2/10 by 51 users Teams of LEGO enthusiasts go head-to-head, with infinite possibilities and an unlimited supply of LEGO bricks. Teams of two will compete against each other in ambitious brick-building challenges to be crowned the country's most talented amateur LEGO builders. Based on the hit British reality-competition series of the same name. Details Casts Posters Images Title LEGO Masters - Celebrity Holiday Bricktacular Alternative Titles Lego Masters (US), Lego Masters US, LEGO Masters: Celebrity Holiday Bricktacular First Air Date 2020-02-05 Last Air Date 2025-07-28 Number of Episodes 65 Number of Seasons 6 Genres Family, Reality, Networks FOX, Casts Will Arnett, Jamie Berard, Amy Corbett Plot Keywords , Self - Host Will Arnett Self - Judge Jamie Berard Self - Judge Amy Corbett Episodes List LEGO Masters Season 5 :Episode 1 Celebrity Holiday Bricktacular: Home Alone Celebrity Holiday Bricktacular: Home Alone 2024-12-10 Teams of LEGO enthusiasts go head-to-head, with infinite possibilities and an unlimited supply of LEGO bricks. Teams of two will compete against each... LEGO Masters Season 5 :Episode 2 Celebrity Holiday Bricktacular: Reindeer Replacement Celebrity Holiday Bricktacular: Reindeer Replacement 2024-12-10 Teams of LEGO enthusiasts go head-to-head, with infinite possibilities and an unlimited supply of LEGO bricks. Teams of two will compete against each... LEGO Masters Season 5 :Episode 3 Celebrity Holiday Bricktacular: Winter Break Celebrity Holiday Bricktacular: Winter Break 2024-12-17 Teams of LEGO enthusiasts go head-to-head, with infinite possibilities and an unlimited supply of LEGO bricks. Teams of two will compete against each... LEGO Masters Season 5 :Episode 4 Celebrity Holiday Bricktacular: New Holiday Classics Celebrity Holiday Bricktacular: New Holiday Classics 2024-12-17 Teams of LEGO enthusiasts go head-to-head, with infinite possibilities and an unlimited supply of LEGO bricks. Teams of two will compete against each...